### Two way to two...

If x=1.999...infinity, then 10x=19.999...infinity. Subtracting 10x from x gives 9x=18. Dividing both sides results in x=2.

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1.99.. does equal 2

1.99.. = 1.99..

1.99.. = 1+ .99..

1.99.. = 1 + 9 * .11..

1.99.. = 1 + 9 * 1/9

1.99.. = 1 + 1

1.99.. = 2

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Because .9999... means a decimal with an infinite number of nines after it, the only possible value for 1-.9999... would be .0000000....1 in other words, an infinite number of zeroes..... followed by a one. Clearly, this is absurd, and therefore 1-.999999... must be zero.

As fun as these are, as far as I can tell, they aren't based on real math. I think 1.999... = 2 by definition.

## 5 comments:

Warning, lots of related BS here: http://2ndglance.blogspot.com/2005/11/two-way-to-two.html

I wonder which parts of the cat/cats are missing when there is only 1.999 of them?

It's all good.

I can't beleive I just read this whole thread :(

http://forums.macrumors.com/archive/index.php/t-57245.html

Well if by 1.999 you mean 1.9999999... 9's forever, then none of them are missing because just as .3333... = 1/3 and .66666... = 2/3, .9999... = 3/3 and any number divided by itself is one (1). .9999... is just a fancy waying of expressing the concept of one (1). Just as the Romans expressed 13 as XIII.

Makes sense and I agree!

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